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Magnetic moment of V(Z = 23),Cr(Z = 24)...

Magnetic moment of `V(Z = 23),Cr(Z = 24),and Mn(Z= 25)` are ` x,y,z `repectively hence

A

`x=y=z`

B

`xltyltz`

C

`xltzlty`

D

`zltyltx`

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Magnetic moment of V(Z = 23),Cr(Z = 24),and Mn(Z= 25) are x,y,z respectively hence

Transition metals and many of their compounds show paramagnetic behaviour where there are unpaired electron or electrons. The magnetic moment arises from the spin and orbital motions in ions or molecule. Magnetic moment of n unpaired electrons is given as mu=sqrt(n(n+2)) Bohr magneton Magnetic moment increases as the number of unpaired electrons increases. Q. Magnetic moments of Cr(Z=24),Mn^(o+)(Z=35) and Fe^(2+)(Z=36) are x,y and z respectively. Which of the following order is correct?

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Among V(Z=23) , Cr(Z=24) , Mn(Z=25) and Fe(Z=26) , which will have the highest magnetic moment?

Spin magnetic moment of X^(n+) (Z=26) is sqrt(24) B.M. Hence number of unpaired electrons and value of n respectively are:

The point charges + q, -2q and + q are placed at point (x = 0, y = a, z = 0), (x = 0, y = 0, z = 0) and (x = a, y = 0, z = 0) , repectively. The magnitude and direction of the electric dipole moment vector of this charge assembly are

The E^(@) value in respect of the electrodes chromium (Z=24) , manganese (Z=25) and iron (Z=26) are : Cr^(3+)//Cr^(2+)=-0.4V,Mn^(3+)//Mn^(2+)=+1.5V , " " Fe^(3+)//Fe^(2)=+0.8V . On the basic of the above information compare the feasibilities of further oxidation of their +2 oxidation states.

Which of the followig ions will show highest magnetic moment (Z values for nautral atoms are as follows: N = 7, Cr = 24, Fe = 26 & Co = 27)

Out of the following transition elements, the maximum number of oxidation states are shown by (a) Sc(Z=21) (b) Cr (Z=24) (c) Mn (Z=25) (d) Fe (Z=26)

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