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If 0.5 mole H(2) is reacted with 0.5 mol...

If `0.5 `mole `H_(2)` is reacted with 0.5 mole `I_(2)` in a ten `-` litre container at `444^(@)C` and at same temperature value of equilibrium constant `K_(C)` is 49, the ratio of `[Hl]` and `[l_(2)]` will be `:`

A

7

B

`(1)/(7)`

C

`sqrt((1)/(7))`

D

49

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