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N(2)O(4(g))rArr2NO(2),K(c)5.7xx10^(-9) ...

`N_(2)O_(4(g))rArr2NO_(2),K_(c)5.7xx10^(-9)` at 298 K At equilibrium :-

A

concentration of `NO_(2)` is higher than that of `N_(2)O_(4)`

B

concentration of `N_(2)O_(4)` is higher than of `NO_(2)`

C

both `N_(2)O_(4) and NO_(2)` have same concentration

D

concentration of `N_(2)O_(4) and NO_(2)` keeps on changing

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To solve the problem regarding the equilibrium of the reaction \( N_2O_4(g) \rightleftharpoons 2NO_2(g) \) with the equilibrium constant \( K_c = 5.7 \times 10^{-9} \) at 298 K, we will analyze the implications of the given equilibrium constant. ### Step-by-Step Solution: 1. **Write the expression for the equilibrium constant \( K_c \)**: The equilibrium constant for the reaction can be expressed as: \[ K_c = \frac{[NO_2]^2}{[N_2O_4]} \] where \([NO_2]\) is the concentration of nitrogen dioxide and \([N_2O_4]\) is the concentration of dinitrogen tetroxide at equilibrium. 2. **Substitute the value of \( K_c \)**: Given that \( K_c = 5.7 \times 10^{-9} \), we can substitute this value into the equilibrium expression: \[ 5.7 \times 10^{-9} = \frac{[NO_2]^2}{[N_2O_4]} \] 3. **Analyze the value of \( K_c \)**: The value of \( K_c \) is very small (much less than 1), which indicates that at equilibrium, the concentration of the reactants (in this case, \( N_2O_4 \)) is much greater than the concentration of the products (\( NO_2 \)). This means that the reaction favors the formation of the reactants. 4. **Conclude the relationship between concentrations**: Since \( K_c \) is small, we conclude that: \[ [N_2O_4] > [NO_2] \] This implies that at equilibrium, the concentration of \( N_2O_4 \) is higher than that of \( NO_2 \). 5. **Evaluate the statements**: Based on our analysis, we can evaluate the given statements: - Concentration of \( NO_2 \) is higher: **Incorrect** - Concentration of \( N_2O_4 \) is higher than \( NO_2 \): **Correct** - Both have the same concentration: **Incorrect** - Concentration of \( N_2O_4 \) and \( NO_2 \) keeps on changing: **Incorrect** Thus, the correct statement is that the concentration of \( N_2O_4 \) is higher than that of \( NO_2 \).
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