Which of the following Sol is formed due to following Rxn :- `SnO_(2)+HCl` (Excess) :-

Options

A. `[SnCl_(4)]Cl^(-)`
B. `[SnCl_(4)]O^(-2)`
C. `[SnCl_(4)]H^(+)`
D. None

Answer

To solve the question regarding the sol formed from the reaction of SnO₂ with excess HCl, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in the reaction are:
- SnO₂ (tin(IV) oxide)
- HCl (hydrochloric acid)

### Step 2: Understand the Reaction
When SnO₂ reacts with HCl, the excess HCl will lead to the formation of a soluble tin chloride. The reaction can be represented as:
\[ \text{SnO}_2 + 4 \text{HCl} \rightarrow \text{SnCl}_4 + 2 \text{H}_2\text{O} \]

### Step 3: Identify the Product
From the reaction, we see that SnCl₄ (tin(IV) chloride) is formed along with water. The chloride ions (Cl⁻) from HCl are also present in the solution.

### Step 4: Determine the Type of Sol
The product formed, SnCl₄, along with Cl⁻ ions, indicates that we have a colloidal solution (sol). This is because SnCl₄ can exist in a colloidal form when it interacts with water.

### Step 5: Conclusion
Thus, the sol formed due to the reaction of SnO₂ with excess HCl is SnCl₄ in the presence of Cl⁻ ions.

### Final Answer
The correct sol formed from the reaction is **SnCl₄**.

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