Graph between `log, x/m` and log p is a strainght line at angle fo `45^(@)` with intercept `0.4771 on
y-axis. Calculate the amount of the gas adsorbed in gm per gm of adsorbent when pressure is 3
atm.

Options

A. `0.4`
B. `0.6`
C. `0.8`
D. `0.2`

Answer

A

Explanation

`"log"(X)/(M)="log K"+(1)/(n)"log P"`
`Y = C + MX`
intercept (c ) = 0.30
log K = 0.30
`K = 10^(0.3)=2`
`(1)/(n)=tan 45 = 1`
`(1)/(n)=1`
`"log"(X)/(M)=0.30+1xx log 0.2`
`0.30-0.70=-0.40`
`(X)/(M)=10^(-0.40)=10^(-1)xx10^(0.60)=4xx10^(-1)=0.4`