Assertion: Reaction of `SO_(2)` and `H_(2)S` in the presence of `Fe_(2)O_(3)` catalyst gives elemental sulphur.
Reason: `SO_(2)` is a reducing agent.

Options

A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
B. If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.
C. If Assertion is True but the Reason is False.
D. If both Assertion & Reason are False.

Answer

To solve the question, we will analyze both the assertion and the reason provided.

### Step 1: Analyze the Assertion
The assertion states that the reaction of \( SO_2 \) and \( H_2S \) in the presence of \( Fe_2O_3 \) catalyst gives elemental sulfur.

**Reaction:**
\[ SO_2 + 2H_2S \xrightarrow{Fe_2O_3} 2H_2O + S \]

This reaction is indeed correct. The presence of \( Fe_2O_3 \) as a catalyst facilitates the reaction, leading to the formation of elemental sulfur.

### Step 2: Verify the Assertion
The reaction can be balanced as follows:
- On the reactant side, we have 1 sulfur atom from \( SO_2 \) and 2 sulfur atoms from \( H_2S \), totaling 3 sulfur atoms.
- On the product side, we have 1 sulfur atom in elemental sulfur.

Thus, the assertion is true because the reaction does produce elemental sulfur.

### Step 3: Analyze the Reason
The reason states that \( SO_2 \) is a reducing agent.

**Oxidation States:**
- In \( SO_2 \), sulfur has an oxidation state of +4.
- In elemental sulfur (S), the oxidation state is 0.
- In \( H_2S \), sulfur has an oxidation state of -2.

In this reaction, \( H_2S \) acts as a reducing agent because it donates electrons (is oxidized) to \( SO_2 \), which is reduced from +4 to 0. Therefore, \( SO_2 \) is acting as an oxidizing agent, not a reducing agent.

### Step 4: Conclusion
Since the assertion is true and the reason is false, the correct conclusion is that the assertion is true but the reason is false.

### Final Answer
- Assertion: True
- Reason: False
- Therefore, the correct option is C: Assertion is true but reason is false.

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