Match List I with List II and select the correct answer using the codes given below the list :
`{:(,"List I","List II",),(1.,"Heavy water",(a)"Bicarbonates of Mg and Ca in water",),(2.,"Temporary hard water",(b)"No foreign ions in water",),(3.,"Soft water",(c)D_(2)O,),(4.,"Permanent hard water",(d)"Sulphates and chlorides of Mg and Ca in water.",):}`

Options

A. 1-C, 2-D, 3-B, 4-A
B. 1-B, 2-A, 3-C, 4-D
C. 1-B, 2-D, 3-C, 4-A
D. 1-C, 2-A, 3-B, 4-D

Answer

To solve the problem of matching List I with List II, we will analyze each item in List I and find its corresponding match in List II.

### Step-by-Step Solution:

1. **Identify Heavy Water:**
- Heavy water is chemically represented as D₂O, which contains deuterium, an isotope of hydrogen.
- **Match:** Heavy water (1) corresponds to (c) D₂O.

2. **Identify Temporary Hard Water:**
- Temporary hard water contains bicarbonates of calcium and magnesium. It can be softened by boiling.
- **Match:** Temporary hard water (2) corresponds to (a) Bicarbonates of Mg and Ca in water.

3. **Identify Soft Water:**
- Soft water is water that is free from dissolved salts, particularly calcium and magnesium salts. It does not contain foreign ions.
- **Match:** Soft water (3) corresponds to (b) No foreign ions in water.

4. **Identify Permanent Hard Water:**
- Permanent hard water contains dissolved minerals such as sulfates and chlorides of calcium and magnesium. This type of hardness cannot be removed by boiling.
- **Match:** Permanent hard water (4) corresponds to (d) Sulphates and chlorides of Mg and Ca in water.

### Summary of Matches:
- 1 → c (Heavy water → D₂O)
- 2 → a (Temporary hard water → Bicarbonates of Mg and Ca in water)
- 3 → b (Soft water → No foreign ions in water)
- 4 → d (Permanent hard water → Sulphates and chlorides of Mg and Ca in water)

### Final Answer:
The correct matching is:
- 1 → c
- 2 → a
- 3 → b
- 4 → d

Thus, the correct answer code is **D**.

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