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Assertion (A) Decomposition of H(2)O(2) ...

Assertion (A) Decomposition of `H_(2)O_(2)` is a disproportionation reaction.
Reason (R ) `H_(2)O_(2)` molecule simultaneously undergoes oxidation and reduction.

A

If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.

B

If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.

C

If Assertion is True but the Reason is False.

D

If both Assertion & Reason are False.

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The correct Answer is:
To solve the question regarding the assertion and reason about the decomposition of hydrogen peroxide (H₂O₂), we will analyze both statements step by step. ### Step 1: Understand the Assertion The assertion states that the decomposition of H₂O₂ is a disproportionation reaction. **Disproportionation Reaction Definition**: A disproportionation reaction is a specific type of redox reaction in which a single substance is both oxidized and reduced, resulting in the formation of two different products. ### Step 2: Write the Decomposition Reaction of H₂O₂ The decomposition of hydrogen peroxide can be represented by the following chemical equation: \[ 2 H_2O_2 \rightarrow 2 H_2O + O_2 \] ### Step 3: Determine the Oxidation States Next, we need to analyze the oxidation states of the elements in the reaction: - In H₂O₂, the oxidation state of oxygen is -1. - In H₂O, the oxidation state of oxygen is -2. - In O₂ (molecular oxygen), the oxidation state of oxygen is 0. ### Step 4: Identify Oxidation and Reduction Now, we can identify which species is being oxidized and which is being reduced: - **Reduction**: H₂O₂ (oxidation state of O changes from -1 to -2 in H₂O) - Here, the oxygen is reduced. - **Oxidation**: H₂O₂ (oxidation state of O changes from -1 to 0 in O₂) - Here, the oxygen is oxidized. ### Step 5: Conclusion on Assertion Since H₂O₂ is undergoing both oxidation and reduction during its decomposition, we conclude that the assertion is true: the decomposition of H₂O₂ is indeed a disproportionation reaction. ### Step 6: Understand the Reason The reason states that the H₂O₂ molecule simultaneously undergoes oxidation and reduction. ### Step 7: Conclusion on Reason This statement is also true, as we have shown that H₂O₂ is both oxidized and reduced in the reaction. ### Final Conclusion Both the assertion and the reason are true, and the reason correctly explains the assertion. Therefore, the correct answer is: **Both assertion and reason are true, and reason is the correct explanation of assertion.** ---
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STATEMENT-1: In disproportionation reaction 50% of the substance is oxidised and remaining 50% is reduced. STATEMENT-2: Decomposition of H_(2)O_(2) is not a disproportionation reaction. STATEMENT-3: Both HNO_(2) & H_(3)PO_(3) can undergo disproportionation reaction.

Decomposition of H_(2)O_(2) can be prevented by :

Speed of decomposition of H_(2)O_(2) is reduced by :

Assertion (A) The O-O bond length in H_(2)O_(2) is shorter than that in O_(2) . Reason (R ) H_(2)O_(2) is ionic compound.

Assertion (A) The O-O bond length in H_(2)O_(2) is shorter than that in O_(2) . Reason (R ) H_(2)O_(2) is ionic compound.

Assertion (A): F_(2) undergoes disproportionation reaction. Reason (R ): Fluorine shows both positive and negative oxidation states.

Assertion : Decomposition of hydrogen peroxide is an example of disproportionation reaction. Reason : In a disproportionation reaction, an element in one oxidation state is simultaneously oxidised and reduced .

Assertion (A): Na_(2)S_(2)O_(3) is a salt of unstable acid. Reason (R) : H_(2)S_(2)O_(3) is a polyprotic acid.

Decomposition of H_(2)O_(2) is retarded by : 2H_(2)O_(2)(l) rarr 2H_(2)O(l)+O_(2)(g)

Assertion (A) The decomposition of hydrogen peroxide to form water and oxygen is an example of disproportionation reaction Reason ( R) The oxygen of peroxide is in -1 oxidation state and it is converted to zero oxidation state in O_(2) and -2 oxidation state in H_(2O .

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