At anode in the electrolysis of fused `NaCl`:

Options

A. `Na^(+)` is oxidised
B. `CI^(-1)` is oxidised
C. `CI^(-)` is reduced
D. `Na^(+)` is reduced

Answer

To solve the question regarding the electrolysis of fused NaCl and identify what occurs at the anode, we can follow these steps:

### Step 1: Understand the Process of Electrolysis
Electrolysis involves the decomposition of a compound into its elements by passing an electric current through it. In the case of fused NaCl, we are dealing with sodium ions (Na⁺) and chloride ions (Cl⁻).

**Hint:** Remember that during electrolysis, oxidation occurs at the anode and reduction occurs at the cathode.

### Step 2: Identify the Ions Present
In fused NaCl, the dissociation can be represented as:
- NaCl → Na⁺ + Cl⁻

Here, Na⁺ is the cation and Cl⁻ is the anion.

**Hint:** Write down the ions formed when NaCl is melted to understand what will be present during electrolysis.

### Step 3: Determine the Reactions at the Electrodes
At the anode (positive electrode), oxidation occurs. This means that the anion (Cl⁻) will lose electrons. The half-reaction can be written as:
- 2Cl⁻ → Cl₂ + 2e⁻

At the cathode (negative electrode), reduction occurs. The cation (Na⁺) will gain electrons:
- Na⁺ + e⁻ → Na

**Hint:** Recall that oxidation involves the loss of electrons, while reduction involves the gain of electrons.

### Step 4: Identify the Product at the Anode
From the half-reaction at the anode, we see that chloride ions (Cl⁻) are oxidized to form chlorine gas (Cl₂). Therefore, the product formed at the anode during the electrolysis of fused NaCl is chlorine gas.

**Hint:** Focus on the changes in oxidation states to determine which species is oxidized.

### Step 5: Conclusion
Thus, during the electrolysis of fused NaCl, chlorine gas is produced at the anode.

**Final Answer:** At the anode in the electrolysis of fused NaCl, chlorine (Cl₂) is produced.