In presence of iron, alkali metal react with liquid ammonia and form

Options

A. Metal mixture `+H_(2)`
B. Iron metal mixture `+H_(2)`
C. Metal mixture
D. Metal amide `+H_(2)`

Answer

To solve the question, "In presence of iron, alkali metal reacts with liquid ammonia and forms what?", we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this scenario are alkali metals (like sodium, potassium, etc.) and liquid ammonia (NH3).

2. **Understand the Role of Iron**: Iron acts as a catalyst in this reaction. It facilitates the reaction between alkali metals and ammonia but is not consumed in the process.

3. **Write the General Reaction**: When an alkali metal (M) reacts with liquid ammonia (NH3), the general reaction can be represented as:
\[ 2M + 2NH3 \rightarrow 2MNH2 + H2 \]
Here, M represents the alkali metal.

4. **Formation of Metal Amide**: The product formed in this reaction is a metal amide (MNH2) and hydrogen gas (H2). The metal amide is formed because the alkali metal donates an electron to the ammonia, resulting in the formation of the amide.

5. **Conclusion**: Therefore, the final products of the reaction are metal amide and hydrogen gas.

6. **Select the Correct Option**: Based on the reaction, the correct answer to the question is that alkali metals react with liquid ammonia in the presence of iron to form metal amides and hydrogen gas.

### Final Answer:
The alkali metal reacts with liquid ammonia in the presence of iron to form metal amides (MNH2) and hydrogen gas (H2).