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Which metal will not form superoxide-...

Which metal will not form superoxide-

A

`Li`

B

`Be`

C

`Na`

D

All

Text Solution

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The correct Answer is:
To determine which metal will not form superoxide among Lithium, Beryllium, Sodium, or if all of these metals do not form superoxide, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Superoxides**: Superoxides are a type of compound that contains the superoxide ion (O₂⁻). They are typically formed by certain alkali and alkaline earth metals. 2. **Identifying the Metals**: The metals in question are Lithium (Li), Beryllium (Be), and Sodium (Na). 3. **Analyzing Lithium**: - Lithium primarily forms lithium oxide (Li₂O) and does not form superoxide. - Therefore, Lithium does not form superoxide. 4. **Analyzing Beryllium**: - Beryllium typically forms beryllium oxide (BeO) and also does not form superoxide. - Thus, Beryllium does not form superoxide. 5. **Analyzing Sodium**: - Sodium can form sodium peroxide (Na₂O₂) but does not form superoxide. - Therefore, Sodium also does not form superoxide. 6. **Conclusion**: - Since Lithium, Beryllium, and Sodium do not form superoxide, the answer to the question is that all of these metals (Lithium, Beryllium, and Sodium) do not form superoxide. ### Final Answer: **All of these (Lithium, Beryllium, and Sodium) will not form superoxide.** ---
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Lithium only forms monoxide when heated in oxygen. Sodium forms monoxide and peroxide in excess of oxygen. Other alkali metals form superoxide metals superoxide with oxygen i.e., MO_(2) . The abnormal behaviour of lithium is due to small size. The larger size of higher metals also decides the role in formation of superoxide. All the three anions abstract proton from water. The three anions are raleted to each other as follows: underset("oxide ion")(O^(2-)overset((1)/(2)O_(2))(to)underset("peroxide ion")(O_(2)^(2-))overset(O_(2))(to)underset("superoxide ion")(2O_(2)^(-)) Q. In hydrolysis, the alkali metals oxides, peroxide and superoxide act as:

Lithium only forms monoxide when heated in oxygen. Sodium forms monoxide and peroxide in excess of oxygen. Other alkali metals form superoxide metals superoxide with oxygen i.e., MO_(2) . The abnormal behaviour of lithium is due to small size. The larger size of higher metals also decides the role in formation of superoxide. All the three anions abstract proton from water. The three anions are raleted to each other as follows: underset("oxide ion")(O_(2)^(2-)overset((1)/(2)O_(2))(to)underset("peroxide ion")(O_(2)^(2-))overset(O_(2))(to)underset("superoxide ion")(2O_(2)^(-)) Q. Consider the following reaction : M+O_(2) to MO_(2) (M=alkali metal) (stable superoxide)

Lithium only forms monoxide when heated in oxygen. Sodium forms monoxide and peroxide in excess of oxygen. Other alkali metals form superoxide metals superoxide with oxygen i.e., MO_(2) . The abnormal behaviour of lithium is due to small size. The larger size of higher metals also decides the role in formation of superoxide. All the three anions abstract proton from water. The three anions are raleted to each other as follows: underset("oxide ion")(O_(2)^(2-)overset((1)/(2)O_(2))(to)underset("peroxide ion")(O_(2)^(2-))overset(O_(2))(to)underset("superoxide ion")(2O_(2)^(-)) Q. Which anion is stable towards water: