Dissolving metallic zinc in `NaOH` produces

Options

A. `Zn(OH)_(2)`
B. `Na_(2)ZnO_(2)`
C. `ZnO`
D. `Zn(OH)_(2)+Na_(2)ZnO_(2)`

Explanation

To solve the question of what is produced when metallic zinc is dissolved in sodium hydroxide (NaOH), we can follow these steps:

### Step 1: Understand the Reactants
We are given metallic zinc (Zn) and sodium hydroxide (NaOH).

### Step 2: Identify the Reaction
When zinc reacts with sodium hydroxide, especially in excess, it typically forms a compound known as sodium zincate (Na2ZnO2) along with hydrogen gas (H2).

### Step 3: Write the Balanced Chemical Equation
The reaction can be represented as follows:

\[ \text{Zn} + 2 \text{NaOH} \rightarrow \text{Na}_2\text{ZnO}_2 + \text{H}_2 \]

### Step 4: Identify the Product
From the balanced equation, we can see that the main product formed is sodium zincate (Na2ZnO2), and hydrogen gas is released as a byproduct.

### Conclusion
Thus, dissolving metallic zinc in NaOH produces sodium zincate (Na2ZnO2) and hydrogen gas (H2).

### Final Answer
The correct answer is sodium zincate (Na2ZnO2).

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