On electrolysis of fused `NaCl` the final product is-

Options

A. `Na`
B. `NaOH`
C. `NaClO`
D. `NaClO_(3)`

Answer

To solve the question regarding the electrolysis of fused NaCl and to identify the final product, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Electrolysis**: Electrolysis is a process that uses electrical energy to drive a non-spontaneous chemical reaction. In the case of fused NaCl, we are looking at the breakdown of sodium chloride into its constituent ions.

2. **Dissociation of NaCl**: When NaCl is melted (fused), it dissociates into sodium ions (Na⁺) and chloride ions (Cl⁻):
\[ \text{NaCl (s)} \rightarrow \text{Na}^+ (l) + \text{Cl}^- (l) \]

3. **Identifying the Electrodes**: In electrolysis, there are two electrodes: the cathode (negative electrode) and the anode (positive electrode).
- At the **cathode**, reduction occurs (gain of electrons).
- At the **anode**, oxidation occurs (loss of electrons).

4. **Reactions at the Electrodes**:
- **At the Cathode**: Sodium ions (Na⁺) gain electrons to become sodium metal (Na):
\[ \text{Na}^+ + e^- \rightarrow \text{Na} (s) \]
- **At the Anode**: Chloride ions (Cl⁻) lose electrons to form chlorine gas (Cl₂):
\[ 2 \text{Cl}^- \rightarrow \text{Cl}_2 (g) + 2e^- \]

5. **Final Products**: The products of the electrolysis of fused NaCl are sodium metal (Na) at the cathode and chlorine gas (Cl₂) at the anode. However, since the question asks for the final product, we focus on the solid sodium metal produced at the cathode.

6. **Conclusion**: Therefore, the final product of the electrolysis of fused NaCl is sodium (Na).

### Final Answer:
The final product of the electrolysis of fused NaCl is sodium (Na).