Strong reductant in IIA and IA group is-

Options

A. `Ba,Li`
B. `Li,Be`
C. `Cs,Ba`
D. `Ba,Cs`

Explanation

To determine the strong reductant in the IIA (Group 2) and IA (Group 1) groups of the periodic table, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Groups**:
- Group IA (1A) consists of alkali metals: Lithium (Li), Sodium (Na), Potassium (K), Rubidium (Rb), and Cesium (Cs).
- Group IIA (2A) consists of alkaline earth metals: Beryllium (Be), Magnesium (Mg), Calcium (Ca), Strontium (Sr), and Barium (Ba).

2. **Understand Reducing Agents**:
- A reducing agent (reductant) is a substance that donates electrons in a chemical reaction and is oxidized in the process.
- The strength of a reducing agent generally increases as you move up a group in the periodic table.

3. **Analyze Trends**:
- In Group IA, the reducing ability of alkali metals increases from Li to Cs. However, lithium is known to be the strongest reductant among them.
- In Group IIA, the reducing ability of alkaline earth metals also increases from Be to Ba, but beryllium is the strongest reductant in this group.

4. **Conclusion**:
- By comparing the strongest reductants from both groups, we find that Lithium (Li) from Group IA and Beryllium (Be) from Group IIA are the strongest reductants.
- Therefore, the answer to the question is that the strong reductants in IIA and IA groups are Lithium (Li) and Beryllium (Be).

5. **Final Answer**:
- The correct option is **B** (Lithium and Beryllium).