Which statement will be true for solution, when Ba is dissolved in ammonia:-

Options

A. Solution becomes blue
B. Solution becomes good conductor
C. Solution remains colourless
D. Both (1) and (2) are correct

Answer

To determine which statement is true when barium (Ba) is dissolved in ammonia, we can analyze the behavior of barium in liquid ammonia step by step.

### Step-by-Step Solution:

1. **Identify the Element**:
- We are dealing with barium (Ba), which is an alkaline earth metal.

**Hint**: Remember that alkaline earth metals have specific properties when they react with solvents.

2. **Understand the Reaction**:
- When barium is dissolved in liquid ammonia, it undergoes a reaction where it forms ammoniated ions and ammoniated electrons.

**Hint**: Consider how metals typically react with ammonia and what products are formed.

3. **Formation of Ammoniated Ions**:
- The reaction can be represented as:
\[ \text{Ba} + \text{NH}_3 \rightarrow \text{Ba(NH}_3)_x^{2+} + 2e^{-} \]
- Here, barium forms a complex with ammonia and releases ammoniated electrons.

**Hint**: Focus on the ions produced and their significance in the solution.

4. **Color of the Solution**:
- The presence of ammoniated electrons gives the solution a characteristic blue-black color when light is absorbed.

**Hint**: Think about how the color of a solution can indicate the presence of certain ions or electrons.

5. **Electrical Conductivity**:
- The solution becomes a good conductor of electricity due to the presence of ammoniated ions and electrons.

**Hint**: Recall that the ability to conduct electricity in a solution is linked to the presence of charged particles.

6. **Evaluate the Options**:
- Option 1: Solution becomes blue - **True**.
- Option 2: Solution becomes a good conductor - **True**.
- Option 3: Solution remains colorless - **False**.
- Option 4: Both 1 and 2 are correct - **True**.

**Hint**: Cross-check each option against the observations made during the reaction.

7. **Conclusion**:
- The correct answer is that both option 1 (solution becomes blue) and option 2 (solution becomes a good conductor) are true. Therefore, option 4 is the correct choice.

### Final Answer:
**The correct statement is: Both 1 and 2 are correct.**