When `SiCl_(4)` vapours are passed over hot Mg, the products formed are

Options

A. `SiCl_(2) + MgCl_(2)`
B. `MgSi + Cl_(2)`
C. `Si+ MgCl_(2)`
D. `MgSiCl_(6)`

Explanation

To solve the question "When SiCl₄ vapors are passed over hot Mg, the products formed are," we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are silicon tetrachloride (SiCl₄) in vapor form and magnesium (Mg) in a hot state.

### Step 2: Understand the Reaction
When SiCl₄ is passed over hot magnesium, a chemical reaction occurs. Magnesium acts as a reducing agent, meaning it will donate electrons to another species.

### Step 3: Write the Reaction
The reaction can be represented as follows:
\[ \text{SiCl}_4(g) + 2\text{Mg}(s) \rightarrow \text{Si}(s) + 2\text{MgCl}_2(s) \]

### Step 4: Balance the Reaction
In the balanced equation:
- 1 molecule of SiCl₄ reacts with 2 atoms of magnesium (Mg).
- This produces 1 atom of silicon (Si) and 2 molecules of magnesium chloride (MgCl₂).

### Step 5: Identify the Products
From the balanced equation, the products formed are:
- Silicon (Si)
- Magnesium chloride (MgCl₂)

### Conclusion
Thus, when SiCl₄ vapors are passed over hot Mg, the products formed are silicon and magnesium chloride.

### Final Answer
The products formed are Si and MgCl₂.

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