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Assertion: Beryllium is most reducing s-...

Assertion: Beryllium is most reducing s-block element
Reason: Hydration energy of Be is greater than its I.P.

A

If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion

B

If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion

C

If Assertion is True but the Reason is False

D

If both Assertion & Reason are False

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AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze both the assertion and the reason provided. ### Step 1: Analyze the Assertion **Assertion:** Beryllium is the most reducing s-block element. - Beryllium (Be) is a Group 2 element in the s-block of the periodic table. - Reducing agents are substances that can donate electrons easily. - In general, elements with lower ionization energies tend to be better reducing agents because they can lose electrons more readily. ### Step 2: Understand Ionization Energy - Beryllium has the highest ionization energy among the Group 2 elements due to its small atomic size and effective nuclear charge. - Higher ionization energy means it is less likely to lose electrons, which contradicts the assertion that it is the most reducing agent. ### Step 3: Analyze the Reason **Reason:** The hydration energy of Be is greater than its ionization potential. - Hydration energy refers to the energy released when ions are solvated by water molecules. - For beryllium, the hydration energy is indeed significant due to its small size and high charge density. - However, the statement that the hydration energy is greater than its ionization potential is incorrect. In fact, the ionization energy of beryllium is greater than its hydration energy. ### Step 4: Conclusion - Since the assertion is incorrect (Beryllium is not the most reducing s-block element) and the reason is also incorrect (the hydration energy is not greater than the ionization potential), we conclude that both the assertion and reason are false. ### Final Answer - Both the assertion and the reason are false. Therefore, the correct choice is option D.

To solve the question, we need to analyze both the assertion and the reason provided. ### Step 1: Analyze the Assertion **Assertion:** Beryllium is the most reducing s-block element. - Beryllium (Be) is a Group 2 element in the s-block of the periodic table. - Reducing agents are substances that can donate electrons easily. - In general, elements with lower ionization energies tend to be better reducing agents because they can lose electrons more readily. ...
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ALLEN-S-BLOCK ELEMENTS -EXERCISE
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  2. Which of the following statement is correct for s-block elements:

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  3. One element which is used in flash light in photography, when heated w...

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  4. The s-block hydride with covalent polymeric structure are

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  5. Assertion: Na(2)O(2) is coloured and paramagnetic Reason: Na(2)O(2) ...

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  6. Assertion: KHCO(3) can not be obtained by solvay process. Reason: KH...

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  7. Assertion: Mg can burn in the atmosphere of N(2). Reason: Mg reacts ...

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  8. Assertion: Li(2)SO(4) do not form double salt like alum. Reason: Ato...

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  9. Assertion: Li and Mg shows similar chemical properties. Reason Li an...

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  10. Assertion: NaCI when exposed in air it becomes wet. Reason: NaCI con...

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  11. Assertion: Lithium is most reducing element. Reason: IP of lithium i...

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  12. Assertion: Lithium is the weakest reducing agent among alkali metals. ...

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  13. Assertion: When cement is mixed with water and left as such, it become...

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  14. Assertion: Beryllium is most reducing s-block element Reason: Hydrat...

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  15. Assertion: Halides of Be dissolve in organic solvents Reason: Atomic...

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  16. Assertion: Be has complex formation tendency Reason: Be is s-block e...

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  17. Assertion: Be exhibit photoelectric effect. Reason: Be has least IP ...

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  18. Assertion: In Down's process CaCI(2) and NaF is added with fused NaCI ...

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  19. Assertion: Chlorides of Li, Be and Mg are covalent in nature Reason:...

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  20. Assertion (A): Barium is not required for normal biological function i...

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