Oxidation number of `Cl` in `NOClO_(4)` is:

Options

A. `+11`
B. `+9`
C. `+7`
D. `+5`

Explanation

To find the oxidation number of chlorine (Cl) in the compound NOClO₄, we can follow these steps:

### Step 1: Identify the components of the compound
The compound NOClO₄ can be broken down into two parts:
- NO (nitric oxide)
- ClO₄⁻ (perchlorate ion)

### Step 2: Understand the oxidation states
- The oxidation state of oxygen (O) is typically -2.
- The overall charge of the ClO₄⁻ ion is -1.

### Step 3: Set up the equation for the oxidation state of Cl
Let the oxidation number of Cl be represented by \( X \). In the ClO₄⁻ ion, we have:
\[ X + 4(-2) = -1 \]

### Step 4: Solve the equation
Now, we can simplify the equation:
\[ X - 8 = -1 \]
Adding 8 to both sides gives:
\[ X = -1 + 8 \]
\[ X = +7 \]

### Step 5: Conclusion
Thus, the oxidation number of chlorine (Cl) in NOClO₄ is +7.

### Final Answer:
The oxidation number of Cl in NOClO₄ is +7.

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