`-1//3` oxidation state of nitrogen will be obtained in case of :

Options

A. Ammonia `(NH_(3))`
B. Hydrazoic acid `(N_(3)H)`
C. Nitric oxide `(NO)`
D. Nitrous oxide `(N_(2)O)`

Answer

To determine the oxidation state of nitrogen in the given compounds, we will analyze each option step by step.

### Step-by-Step Solution:

1. **Identify the Compounds:**
We need to analyze the oxidation state of nitrogen in four different compounds. Let's denote them as A, B, C, and D.

2. **Analyze Compound A:**
- Assume the oxidation state of nitrogen in compound A is \( x \).
- The compound contains 3 hydrogen atoms, each with an oxidation state of +1.
- The equation for the compound can be set up as:
\[ x + 3(+1) = 0 \]
- Simplifying this gives:
\[ x + 3 = 0 \implies x = -3 \]
- Therefore, the oxidation state of nitrogen in compound A is -3.

3. **Analyze Compound B:**
- Assume the oxidation state of nitrogen in compound B is \( x \).
- The compound contains 3 nitrogen atoms and 1 hydrogen atom.
- The equation can be set up as:
\[ 3x + 1(+1) = 0 \]
- Simplifying this gives:
\[ 3x + 1 = 0 \implies 3x = -1 \implies x = -\frac{1}{3} \]
- Therefore, the oxidation state of nitrogen in compound B is -1/3.

4. **Analyze Compound C:**
- Assume the oxidation state of nitrogen in compound C is \( x \).
- The compound contains 1 nitrogen atom and 2 oxygen atoms (with an oxidation state of -2).
- The equation can be set up as:
\[ x + 2(-2) = 0 \]
- Simplifying this gives:
\[ x - 4 = 0 \implies x = 4 \]
- Therefore, the oxidation state of nitrogen in compound C is +4.

5. **Analyze Compound D:**
- Assume the oxidation state of nitrogen in compound D is \( x \).
- The compound contains 2 nitrogen atoms and 2 oxygen atoms.
- The equation can be set up as:
\[ 2x + 2(-2) = 0 \]
- Simplifying this gives:
\[ 2x - 4 = 0 \implies 2x = 4 \implies x = 2 \]
- Therefore, the oxidation state of nitrogen in compound D is +2.

6. **Conclusion:**
- After analyzing all four compounds, we find that only in compound B does nitrogen have an oxidation state of -1/3.

### Final Answer:
The oxidation state of nitrogen that will be obtained is **-1/3** in compound B.