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In the reaction : MnO(4)^(-)+xH^(+)+n e^...

In the reaction : `MnO_(4)^(-)+xH^(+)+n e^(-)rarrMn^(2+)+yH_(2)O` What is the value of n :

A

5

B

8

C

6

D

3

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The correct Answer is:
To determine the value of \( n \) in the reaction: \[ \text{MnO}_4^{-} + x\text{H}^{+} + n e^{-} \rightarrow \text{Mn}^{2+} + y\text{H}_2\text{O} \] we will follow these steps: ### Step 1: Determine the change in oxidation state - The oxidation state of manganese in \(\text{MnO}_4^{-}\) is \( +7 \). - The oxidation state of manganese in \(\text{Mn}^{2+}\) is \( +2 \). - The change in oxidation state is calculated as: \[ \text{Change} = +7 - (+2) = 5 \] ### Step 2: Balance the manganese atoms - There is one manganese atom on both sides of the equation: \[ \text{1 Mn on the left} \quad \text{and} \quad \text{1 Mn on the right} \] - Therefore, the manganese atoms are already balanced. ### Step 3: Balance the oxygen atoms - The left side has 4 oxygen atoms from \(\text{MnO}_4^{-}\). - We can balance the oxygen atoms by adding water (\(\text{H}_2\text{O}\)) on the right side: \[ \text{4 O from } \text{MnO}_4^{-} \rightarrow \text{4 H}_2\text{O} \] - Thus, \( y = 4 \). ### Step 4: Balance the hydrogen atoms - Each water molecule contributes 2 hydrogen atoms. Therefore, 4 water molecules contribute: \[ 4 \times 2 = 8 \text{ H atoms} \] - To balance the 8 hydrogen atoms, we need to add \( 8 \text{H}^{+} \) ions on the left side: \[ x = 8 \] ### Step 5: Balance the charge - Now we need to balance the charges on both sides of the equation. - On the left side: \[ \text{Charge} = -1 (\text{from } \text{MnO}_4^{-}) + 8 (\text{from } 8\text{H}^{+}) = +7 \] - On the right side: \[ \text{Charge} = +2 (\text{from } \text{Mn}^{2+}) \] - To balance the charges, we need to add electrons (\( e^{-} \)) to the left side. Let \( n \) be the number of electrons: \[ +7 - n = +2 \] - Rearranging gives: \[ n = 7 - 2 = 5 \] ### Conclusion The value of \( n \) is \( 5 \). ### Summary - The balanced reaction is: \[ \text{MnO}_4^{-} + 8\text{H}^{+} + 5 e^{-} \rightarrow \text{Mn}^{2+} + 4\text{H}_2\text{O} \]
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ALLEN-REDOX REACTIONS-Exercise - 1
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  11. In a reaction 4 mole of electrons are transferred to one mole of HNO(3...

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  12. Balance given following half reaction for the unbalanced whole reactio...

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  13. Choose the set coefficients that correctly balances the following equa...

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  14. In the reaction : MnO(4)^(-)+xH^(+)+n e^(-)rarrMn^(2+)+yH(2)O What is ...

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  18. The value of n in, MnO4^(-)+8H^(+)+"ne"^(-)rarrMn^(2-)+4H2O is

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