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The enthalpy change (Delta H) for the re...

The enthalpy change `(Delta H)` for the reaction, `N_(2)(g)+3H_(2)(g)to 2NH_(3)(g)` is -92.3 kJ at 298 K. What is `Delta U` at 298 K ?

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`Delta U=Delta H-Delta n_(g)RT=-92.38-(-2)xx(8.314)/(1000)xx298 = -87.42 kJ`
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