A `5L` cylinder contained `10` moles of oxygen gas at `27^(@)C`. Due to sudden leakage through the hole, all the gas escaped into the atmosphere and the cylinder got empty. If the atmospheric pressure is `1.0atm`, calculate the work done by the gas.

Explanation

`V_("initial")=5` litre, `T=27^(@)C=27+273 = 300 K`
`V_("final")=(nRT)/(P)=(10xx0.0821xx300)/(1)=246.3` litre
`Delta V=V_("final")-V_("initial")=246.3-5=241.3` litre
`W_("exp")=-P Delta V=-1xx241.3` litre `xx` atm. `=-24443.69J=24.4 kJ`
i.e. work done by gas is 24.4 kJ