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For the chemical equilibrium PCl(5)(g)...

For the chemical equilibrium
`PCl_(5)(g) hArr PCl_(3)(g) +Cl_(2) (g) " at " 298K, K_(c )=1.8xx10^(-7)`.
Calculate `Delta_(r )G^(Theta)` for the forward reaction `R=8.31JK^(-1)"mol"^(-1)`

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`Delta G = -2.303 "RT log " K_(p)=-2.303xx8.314xx10^(-3)kJ mol^(-1)K^(-1)xx298 K xx log 1.8xx10^(-7)=38.484 kJ mol^(-1)`
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