`Delta H_(f)^(@)` for `Al_(2)O_(3)` is -1670 KJ. Calculate the enthalpy change for the reaction `4Al+3O_(2)rarr 2Al_(2)O_(3)`

Explanation

To calculate the enthalpy change for the reaction:

\[ 4 \text{Al} + 3 \text{O}_2 \rightarrow 2 \text{Al}_2\text{O}_3 \]

given that the standard enthalpy of formation (\( \Delta H_f^\circ \)) for \( \text{Al}_2\text{O}_3 \) is -1670 kJ, we can follow these steps:

### Step 1: Understand the Reaction
The reaction shows that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide (\( \text{Al}_2\text{O}_3 \)).
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