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Assuming that water vapour is an ideal g...

Assuming that water vapour is an ideal gas, the internal energy change `(DeltaU)` when 1 mol of water is vaporized at 1 bar pressure and `100^(@)`C, (given : molar enthalpy of vaporized of water of 1 bar and 373 K= 41 kJ `mol^(-1)` and `R = 8.314 JK^(-1) mol^(-1)` will beL

A

`4.100 kJ mol^(-1)`

B

`3.7904 kJ mol^(-1)`

C

`37.904 kJ mol^(-1)`

D

`41.00 kJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C

`H_(2)(O)_((l))rarr H_(2)O_((g))`
`Delta H=Delta H+Delta n_(g)RT`
`41=Delta E+1xx8.314xx10^(-3)x373`
`therefore Delta E=37.9 kJ mol^(-1)`
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