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The equilibrium constant for a reaction ...

The equilibrium constant for a reaction is 10. What will be the value of `DeltaG^(theta)`?
`R=8.314 JK^(-1)mol^(-1)T=300JK.`

A

`+5.527 KJ mol^(-1)`

B

`-5.527 KJ mol^(-1)`

C

`+55.27 KJ mol^(-1)`

D

`-55.27 KJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`Delta G^(@)=-2.303` RT log K
`=-2.303xx8 5 10^(-3)xx300xxlog 10`
`Delta G^(@)=-5.527 kJ mol^(-1)`
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