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For the process, CO(2)(s) to CO(2)(g)...

For the process, `CO_(2)(s) to CO_(2)(g)`

A

Both `Delta H` and `Delta S` are +ve

B

`Delta H` is negative and `Delta S` is +ve

C

`Delta H` is + ve and `Delta S` is -ve

D

Both `Delta H` and `Delta S` are -ve

Text Solution

Verified by Experts

The correct Answer is:
A
It is sublimation process so, endothermic `(Delta H gt 0)` process. The entropy of gas is greater than solid so `Delta S gt 0`.
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