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If C(6)H(12)O(6)(s) +6O(2)(g) to 6CO(2)(...

If `C_(6)H_(12)O_(6)(s) +6O_(2)(g) to 6CO_(2)(g)+6H_(2)O (l), triangleH=680` Kcal.
The mass of `CO_(2)(g)` produced when 170 Kcal of heat is evolved in the combustion of glucose is

A

265 gm

B

66 gm

C

11 gm

D

64 gm

Text Solution

Verified by Experts

The correct Answer is:
B
`C_(6)H_(12)O_(6(s))+9O_(2(g))rarr 5CO_(2(g))+6H_(2)O_((g)) , Delta H=-680 KCal` .
680 Kcal heat is released when 6 mole `CO_(2)` is produced so,
170 KCal heat is released when `((6)/(680)xx170)` mole `CO_(2)` is produced.
`therefore` Mass of `CO_(2)` produced `=(6)/(680)xx170xx44 g`
`=66 g CO_(2)`
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