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If S+O(2)toSO(2),DeltaH=-298.2 " kJ" " m...

If `S+O_(2)toSO_(2),DeltaH=-298.2 " kJ" " mole"^(-1)`
`SO_(2)+(1)/(2)O_(2)toSO_(3)DeltaH=-98.7 " kJ" " mole"^(-1)`
`SO_(3)+H_(2)OtoH_(2)SO_(4),DeltaH=-130.2 " kJ" " mole"^(-1)`
`H_(2)+(1)/(2)O_(2)toH_(2)O,DeltaH=-287.3 " kJ" " mole"^(-1)`
the enthlapy of formation of `H_(2)SO_(4)` at 298 K will be

A

`-814.4` KJ

B

`-650.3` KJ

C

`-320.5` KJ

D

`-433.5` KJ

Text Solution

Verified by Experts

The correct Answer is:
A
`H_(2(g))+S_((s))+2O_(2(g))rarr H_(2)SO_(4) , Delta H_(f) = ?`
Desired equation = eq(i) + eq(iii) + eq(iv) + eq(ii)
`Delta H_(f)=(-298.2)+(-130.2)+(-287.3)+(-98.7)`
`Delta H_(f)=-814.4 KJ`
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