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Find the heat change in the reaction: ...

Find the heat change in the reaction:
`NH_3(g)+HCI(g) to NH_4CI(s)`
from the following data
`NH_(3)(g)+aq to NH_(3)(aq) triangleH=-8.4KCal`
`HCl(g)+aq to HCl (aq) triangleH=-17.3KCal`
`NH_(3)(aq)+HCl(aq) to NH_(4)Cl(aq) triangleH=-12.5KCal`
`NH_(4)Cl(s) +aq to NH_(4)Cl(aq) triangleH=+3.9Kcal`

A

`-42.1`

B

`-34.3`

C

`+34.3`

D

`+42.1`

Text Solution

Verified by Experts

The correct Answer is:
A
`NH_(3(g))+HCl_((g))rarr NH_(4)Cl_((s)), Delta H = ?`
Desired equation = eq(i) + eq(ii) + eq(iii) - eq(iv)
`Delta H=(-8.4)+(-17.3)+(-12.5)-(3.9)`
`Delta H =-42.1 KCal`
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