Which of the following element never from compound in ground state : -

Options

A. N
B. B
C. C
D. P

Answer

To determine which element never forms a compound in its ground state, we need to analyze the electronic configurations of the given elements and their ability to form bonds. Let's go through the steps systematically:

### Step 1: Identify the Elements
The elements provided in the question are:
- Nitrogen (N)
- Boron (B)
- Carbon (C)
- Phosphorus (P)

### Step 2: Write the Electronic Configurations
Next, we write the electronic configurations for each element:
- **Nitrogen (N)**: 1s² 2s² 2p³
- **Boron (B)**: 1s² 2s² 2p¹
- **Carbon (C)**: 1s² 2s² 2p²
- **Phosphorus (P)**: 1s² 2s² 2p⁶ 3s² 3p³

### Step 3: Analyze Bond Formation
Now, we analyze the ability of each element to form compounds based on their valence electrons:

1. **Nitrogen (N)**:
- Valence electrons: 5 (2s² 2p³)
- Can form up to 3 bonds (due to 3 unpaired electrons).
- **Conclusion**: Can form compounds in ground state.

2. **Boron (B)**:
- Valence electrons: 3 (2s² 2p¹)
- Has only 1 unpaired electron, which means it can form only 1 bond.
- If it forms a bond, its octet will be incomplete (it will not satisfy the octet rule).
- **Conclusion**: Cannot form compounds in ground state.

3. **Carbon (C)**:
- Valence electrons: 4 (2s² 2p²)
- Can form up to 4 bonds (due to 4 unpaired electrons).
- **Conclusion**: Can form compounds in ground state.

4. **Phosphorus (P)**:
- Valence electrons: 5 (3s² 3p³)
- Can form up to 3 bonds (due to 3 unpaired electrons).
- **Conclusion**: Can form compounds in ground state.

### Step 4: Final Conclusion
Based on the analysis, the element that never forms a compound in its ground state is **Boron (B)**.

### Answer
The answer to the question is **Boron (B)**.

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