When you move from equator to pole, the value of acceleration due to gravity (g) :-

Options

A. increases
B. decreases
C. remains the same
D. first increases then decreases

Answer

To solve the question regarding the change in the value of acceleration due to gravity (g) when moving from the equator to the poles, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Shape of the Earth**:
- The Earth is not a perfect sphere; it has a slight bulge at the equator. This means that the radius of the Earth at the equator is greater than the radius at the poles.

2. **Identifying the Radii**:
- Let \( R_{eq} \) be the radius of the Earth at the equator and \( R_{p} \) be the radius at the poles. We know that \( R_{eq} > R_{p} \).

3. **Acceleration Due to Gravity Formula**:
- The acceleration due to gravity \( g \) at a distance \( r \) from the center of the Earth is given by the formula:
\[ g = \frac{GM}{r^2} \]
where \( G \) is the gravitational constant and \( M \) is the mass of the Earth.

4. **Comparing g at Equator and Poles**:
- Since \( g \) is inversely proportional to the square of the radius \( r \), we can say:
\[ g_{eq} = \frac{GM}{R_{eq}^2} \quad \text{and} \quad g_{p} = \frac{GM}{R_{p}^2} \]
- Because \( R_{eq} > R_{p} \), it follows that:
\[ R_{eq}^2 > R_{p}^2 \]
- Therefore, since \( g \) is inversely proportional to \( r^2 \):
\[ g_{eq} < g_{p} \]

5. **Conclusion**:
- As one moves from the equator to the poles, the value of \( g \) increases. Thus, the correct answer is that the acceleration due to gravity increases.

### Final Answer:
- When moving from the equator to the poles, the value of acceleration due to gravity (g) **increases**.

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