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The figure shows elliptical orbit of a planet m about the sun S. The shaded area SCD is twice the shaded area SAB. If `t_(1)` is the time for the planet to move from C to D and `t_(2)` is the time to move from A to B, then

A

`t_(1)=t_(2)`

B

`t_(1) lt t_(2)`

C

`t_(1) = 4t_(2)`

D

`t_(1)=2t_(2)`

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The correct Answer is:
D
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