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Solve the following :- (i)sqrt(sqrt(2)...

Solve the following :-
(i)`sqrt(sqrt(2)/(3))xxsqrt((9)/(2))`
(ii)`sqrt((5)/(6))xxsqrt((3)/(5))`
(iii)`sqrt((3)/(5))divsqrt((27)/(125))`
(iv)`sqrt((4)/(9))divsqrt((64)/(81))`

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The correct Answer is:
Let's solve each part of the question step by step. ### Part (i): Solve \( \sqrt{\frac{\sqrt{2}}{3}} \times \sqrt{\frac{9}{2}} \) **Step 1:** Rewrite the expression using properties of square roots. \[ \sqrt{\frac{\sqrt{2}}{3}} = \frac{\sqrt{2}}{\sqrt{3}} \quad \text{and} \quad \sqrt{\frac{9}{2}} = \frac{\sqrt{9}}{\sqrt{2}} = \frac{3}{\sqrt{2}} \] **Step 2:** Multiply the two fractions. \[ \frac{\sqrt{2}}{\sqrt{3}} \times \frac{3}{\sqrt{2}} = \frac{3 \cdot \sqrt{2}}{\sqrt{3} \cdot \sqrt{2}} = \frac{3}{\sqrt{3}} \] **Step 3:** Simplify the fraction. \[ \frac{3}{\sqrt{3}} = \sqrt{3} \quad \text{(since } \frac{3}{\sqrt{3}} = \sqrt{3} \text{)} \] **Final Answer for Part (i):** \( \sqrt{3} \) --- ### Part (ii): Solve \( \sqrt{\frac{5}{6}} \times \sqrt{\frac{3}{5}} \) **Step 1:** Rewrite the expression using properties of square roots. \[ \sqrt{\frac{5}{6}} = \frac{\sqrt{5}}{\sqrt{6}} \quad \text{and} \quad \sqrt{\frac{3}{5}} = \frac{\sqrt{3}}{\sqrt{5}} \] **Step 2:** Multiply the two fractions. \[ \frac{\sqrt{5}}{\sqrt{6}} \times \frac{\sqrt{3}}{\sqrt{5}} = \frac{\sqrt{3}}{\sqrt{6}} \] **Step 3:** Simplify the fraction. \[ \frac{\sqrt{3}}{\sqrt{6}} = \frac{\sqrt{3}}{\sqrt{3 \cdot 2}} = \frac{\sqrt{3}}{\sqrt{3} \cdot \sqrt{2}} = \frac{1}{\sqrt{2}} \] **Final Answer for Part (ii):** \( \frac{1}{\sqrt{2}} \) --- ### Part (iii): Solve \( \sqrt{\frac{3}{5}} \div \sqrt{\frac{27}{125}} \) **Step 1:** Rewrite the division as multiplication by the reciprocal. \[ \sqrt{\frac{3}{5}} \div \sqrt{\frac{27}{125}} = \sqrt{\frac{3}{5}} \times \sqrt{\frac{125}{27}} \] **Step 2:** Multiply the two fractions. \[ \frac{\sqrt{3}}{\sqrt{5}} \times \frac{5}{3} = \frac{\sqrt{3} \cdot 5}{\sqrt{5} \cdot 3} \] **Step 3:** Simplify the expression. \[ = \frac{\sqrt{3}}{3} \quad \text{(since } \frac{5}{\sqrt{5}} = \sqrt{5} \text{)} \] **Final Answer for Part (iii):** \( \frac{\sqrt{3}}{3} \) --- ### Part (iv): Solve \( \sqrt{\frac{4}{9}} \div \sqrt{\frac{64}{81}} \) **Step 1:** Rewrite the division as multiplication by the reciprocal. \[ \sqrt{\frac{4}{9}} \div \sqrt{\frac{64}{81}} = \sqrt{\frac{4}{9}} \times \sqrt{\frac{81}{64}} \] **Step 2:** Simplify the square roots. \[ \sqrt{\frac{4}{9}} = \frac{2}{3} \quad \text{and} \quad \sqrt{\frac{81}{64}} = \frac{9}{8} \] **Step 3:** Multiply the two fractions. \[ \frac{2}{3} \times \frac{9}{8} = \frac{2 \cdot 9}{3 \cdot 8} = \frac{18}{24} \] **Step 4:** Simplify the fraction. \[ \frac{18}{24} = \frac{3}{4} \] **Final Answer for Part (iv):** \( \frac{3}{4} \) --- ### Summary of Answers: 1. \( \sqrt{3} \) 2. \( \frac{1}{\sqrt{2}} \) 3. \( \frac{\sqrt{3}}{3} \) 4. \( \frac{3}{4} \) ---
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