Home
Class 12
PHYSICS
Given KE=(1)/(2)mv^(2). If m=10kg, v=5m/...

Given `KE=(1)/(2)mv^(2)`. If `m=10kg, v=5m//s` then find the value of KE?

Text Solution

AI Generated Solution

The correct Answer is:
To find the kinetic energy (KE) of an object, we can use the formula: \[ KE = \frac{1}{2} mv^2 \] Where: - \( m \) is the mass of the object, - \( v \) is the velocity of the object. Given: - \( m = 10 \, \text{kg} \) - \( v = 5 \, \text{m/s} \) Now, we will substitute the values of \( m \) and \( v \) into the formula. ### Step 1: Substitute the values into the formula \[ KE = \frac{1}{2} \times 10 \, \text{kg} \times (5 \, \text{m/s})^2 \] ### Step 2: Calculate \( v^2 \) First, calculate \( (5 \, \text{m/s})^2 \): \[ (5 \, \text{m/s})^2 = 25 \, \text{m}^2/\text{s}^2 \] ### Step 3: Substitute \( v^2 \) back into the equation Now substitute \( v^2 \) back into the equation: \[ KE = \frac{1}{2} \times 10 \, \text{kg} \times 25 \, \text{m}^2/\text{s}^2 \] ### Step 4: Calculate \( \frac{1}{2} \times 10 \) Calculate \( \frac{1}{2} \times 10 \): \[ \frac{1}{2} \times 10 = 5 \] ### Step 5: Multiply by \( 25 \, \text{m}^2/\text{s}^2 \) Now multiply: \[ KE = 5 \times 25 \, \text{kg} \cdot \text{m}^2/\text{s}^2 \] ### Step 6: Calculate the final value \[ KE = 125 \, \text{J} \] Thus, the kinetic energy of the object is: \[ \boxed{125 \, \text{J}} \]
Promotional Banner

Topper's Solved these Questions

  • RACE

    ALLEN|Exercise Basic Maths (VECTORS)|60 Videos
  • RACE

    ALLEN|Exercise Basic Maths (Units, Dimensions & Measurements)|30 Videos
  • RACE

    ALLEN|Exercise Basic Maths (Graphs))|29 Videos
  • NEWTONS LAWS OF MOTION

    ALLEN|Exercise EXERCISE-III|28 Videos
  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise Example|1 Videos

Similar Questions

Explore conceptually related problems

The block of mass m_(1) is placed on a wedge of an angle theta , as shown. The block is moving over the inclined surface of the wedge. Friction coefficient between the block and the wedge is mu_(1) , whereas it is mu_(2) between the wedge and the horizontal surface. if mu_(1)=1/2, theta=45^(@), m_(1)=4 kg, m_(2)=5 kg and g=10 m//s^(2) , find minimum value of mu_(2) so that the wedge remains stationary on the surface. express your answer in multiple of 10^(-3)

The block of mass m_(1) is placed on a wedge of an angle theta , as shown. The block is moving over the inclined surface of the wedge. Friction coefficient between the block and the wedge is mu_(1) , whereas it is mu_(2) between the wedge and the horizontal surface. if mu_(1)=1/2, theta=45^(@), m_(1)=4 kg, m_(2)=5 kg and g=10 m//s^(2) , find minimum value of mu_(2) so that the wedge remains stationary on the surface. express your answer in multiple of 10^(-3)

If the acceleration of the block B in the following system is a ( in m//s^(2)) then find out value of 2a//5(g=10m//s^(2)) :

Given Y = 2 xx 10^(11)N//m^(2), rho = 10^(4) kg//m^(3) Find out elongation in rod.

Two blocks A and B are connected by a string as shown as shown in the figure . Friction coefficient of the inclined plane is 0.5 . The mass of the block A is 5 kg. If minimum and maximum values of mass of the block B for which the block A remains in equilibrium are m_(1) and m_(2) then find the value of (m_(2) - m_(1)) [in kg]

A conservative force acts on a 4 kg particle in x direction. The potential energy U(x) is given by U(X) = 40 + (x – 6)^2 , where x is in metre. If it is given that at x = 8 m, KE is 30 J then find the maximum KE of the particle.

The mass m of a body moving with a velocity v is given by m=m_(0)/sqrt(1-v^(2)/c^(2)) where m_(0) = rest mass of body =10 kg and c = speed of light =3xx10^(8) m//s . Find the value of m at v=3xx10^(7) m//s

In a horizontal pipeline of uniform cross section the pressure falls by 8 N//m^(2) between two points separated by 1 km . If oil of density 800 kg//m^(3) flows through the pipe, find the change in KE per kg of oil at these points.

In fig. both pulleys and the string are massless and all the surfaces are frictionless. Given m_(1)=1kg, m_(2)= 2kg, m_(3)=3kg . Find the tension in the string

Calculate the frequency of paritcle wave, when the kinetic energy of a sub-atomic particle is 3.79 xx 10^(-27) J . Hint : KE = (1)/(2) mv^(2) lambda = (h)/(mv) , lambda = ( v)/( v) :. (v)/(v) = (h)/( mv), v= (mv^(2))/( h) = ( 2 xx ( 1)/(2) mv^(2))/( h)

ALLEN-RACE-Basic Maths (Co-ordinate & Algebra)
  1. What is the distance OA for the square shown in figure :-

    Text Solution

    |

  2. Ratio of amplitude for two wave is 3:9 .Find the ratio of intensity?

    Text Solution

    |

  3. Given KE=(1)/(2)mv^(2). If m=10kg, v=5m//s then find the value of KE?

    Text Solution

    |

  4. Calculate the value of x in the following equation :- x^(2)-5x+6=0

    Text Solution

    |

  5. x-y relation is given by y=x^(n) calculate the value of n in the follo...

    Text Solution

    |

  6. 4sqrt(6)xx3sqrt(24)= :-

    Text Solution

    |

  7. If y=propx^(4) Whenx=1000, y=y(1) then find the value of x so that...

    Text Solution

    |

  8. If yx^(2)/(3)="constant" when x=x(1), then y=300, then find the y wh...

    Text Solution

    |

  9. Givne (x)/(y)=(5)/(6) now x is reduced by 62 and the ratio of x and ...

    Text Solution

    |

  10. Given, P prop T on increasing the value of T by 1^(@)C, the value of ...

    Text Solution

    |

  11. If x^(3)=9x, then find all possible values of x :-

    Text Solution

    |

  12. A river 3 m deep and 40 m wide is flowing at the rate of 2 km per hou...

    Text Solution

    |

  13. A room is 12m long, 4m wide and 3m high, what will be the longest bar ...

    Text Solution

    |

  14. root(3)(8^(2)) is equal to :-

    Text Solution

    |

  15. root(5)(16)xxroot(5)(2) is equal t :-

    Text Solution

    |

  16. If x=sqrt(2)-1 then find the value of ((1)/(x)-x)^(3):-

    Text Solution

    |

  17. If m and n are the two natural number such that m^(n)=25, then find th...

    Text Solution

    |

  18. If y-x=80^(@) then find the values of x and y.

    Text Solution

    |

  19. A cube of 2cm edge is cut off into 8 cubes of 1cm edge. What is teir t...

    Text Solution

    |

  20. How many solid spherical balls of radius 2cm and be made by melting a ...

    Text Solution

    |