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With respect to a rectangular cartesian ...

With respect to a rectangular cartesian coordinate system, three vectors are expressed as `veca=4hati -hatj , vecb=-3hati" and "vecc=-hatk` where `hati,hatj,hatk` are unit vectors of axis x,y and z then `hatr` along the direction of sum of these vector is :-

A

`hatr=(1)/(sqrt(3))(hati-hatj-hatk)`

B

`hatr=(1)/(sqrt(2))(hati+hatj-hatk)`

C

`hatr=(1)/(3)(hati-hatj+hatk)`

D

`hatr=(1)/(sqrt(2))(hati+hatj+hatk)`

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The correct Answer is:
To solve the problem, we need to find the resultant vector from the given vectors \(\vec{a}\), \(\vec{b}\), and \(\vec{c}\), and then determine the unit vector in the direction of this resultant vector. ### Step 1: Write down the vectors The vectors are given as: \[ \vec{a} = 4\hat{i} - \hat{j} \] \[ \vec{b} = -3\hat{i} \] \[ \vec{c} = -\hat{k} \] ### Step 2: Sum the vectors To find the resultant vector \(\vec{R}\), we add the three vectors together: \[ \vec{R} = \vec{a} + \vec{b} + \vec{c} \] Substituting the values: \[ \vec{R} = (4\hat{i} - \hat{j}) + (-3\hat{i}) + (-\hat{k}) \] ### Step 3: Combine like terms Now, we combine the components: - For the \(\hat{i}\) component: \(4 - 3 = 1\) - For the \(\hat{j}\) component: \(-1\) - For the \(\hat{k}\) component: \(-1\) Thus, we have: \[ \vec{R} = 1\hat{i} - 1\hat{j} - 1\hat{k} \] or simply: \[ \vec{R} = \hat{i} - \hat{j} - \hat{k} \] ### Step 4: Find the magnitude of the resultant vector The magnitude of \(\vec{R}\) is calculated as: \[ |\vec{R}| = \sqrt{(1)^2 + (-1)^2 + (-1)^2} = \sqrt{1 + 1 + 1} = \sqrt{3} \] ### Step 5: Find the unit vector in the direction of \(\vec{R}\) The unit vector \(\hat{r}\) in the direction of \(\vec{R}\) is given by: \[ \hat{r} = \frac{\vec{R}}{|\vec{R}|} \] Substituting the values: \[ \hat{r} = \frac{\hat{i} - \hat{j} - \hat{k}}{\sqrt{3}} \] ### Final Result Thus, the unit vector along the direction of the sum of these vectors is: \[ \hat{r} = \frac{1}{\sqrt{3}} \hat{i} - \frac{1}{\sqrt{3}} \hat{j} - \frac{1}{\sqrt{3}} \hat{k} \]
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