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Of the following quantities , which one ...

Of the following quantities , which one has the dimensions different from the remaining three?

A

Energy per unit volume

B

Force per unit area

C

Product of voltage and charge per unit volume

D

Angular momentum per unit mass

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of identifying which quantity has a different dimension from the others, we will analyze the dimensions of each option step by step. ### Step 1: Analyze Option A - Energy per Unit Volume - **Definition**: Energy per unit volume is given by \( \frac{E}{V} \). - **Dimensions**: - Energy (E) has dimensions: \( [E] = M L^2 T^{-2} \) - Volume (V) has dimensions: \( [V] = L^3 \) - **Calculation**: \[ \text{Dimensions of } \frac{E}{V} = \frac{M L^2 T^{-2}}{L^3} = M L^{-1} T^{-2} \] ### Step 2: Analyze Option B - Force per Unit Area - **Definition**: Force per unit area is given by \( \frac{F}{A} \). - **Dimensions**: - Force (F) has dimensions: \( [F] = M L T^{-2} \) - Area (A) has dimensions: \( [A] = L^2 \) - **Calculation**: \[ \text{Dimensions of } \frac{F}{A} = \frac{M L T^{-2}}{L^2} = M L^{-1} T^{-2} \] ### Step 3: Analyze Option C - Product of Voltage and Charge per Unit Volume - **Definition**: Voltage (V) multiplied by charge (Q) per unit volume. - **Dimensions**: - Voltage (V) has dimensions: \( [V] = M L^2 T^{-3} I^{-1} \) - Charge (Q) has dimensions: \( [Q] = I T \) - Volume (V) has dimensions: \( [V] = L^3 \) - **Calculation**: \[ \text{Dimensions of } V \cdot Q = (M L^2 T^{-3} I^{-1}) \cdot (I T) = M L^2 T^{-2} \] \[ \text{Dimensions of } \frac{V \cdot Q}{V} = \frac{M L^2 T^{-2}}{L^3} = M L^{-1} T^{-2} \] ### Step 4: Analyze Option D - Angular Momentum per Unit Mass - **Definition**: Angular momentum (L) per unit mass (M). - **Dimensions**: - Angular momentum has dimensions: \( [L] = M L^2 T^{-1} \) - Mass (M) has dimensions: \( [M] = M \) - **Calculation**: \[ \text{Dimensions of } \frac{L}{M} = \frac{M L^2 T^{-1}}{M} = L^2 T^{-1} \] ### Conclusion Now, we can summarize the dimensions of all options: - Option A: \( M L^{-1} T^{-2} \) - Option B: \( M L^{-1} T^{-2} \) - Option C: \( M L^{-1} T^{-2} \) - Option D: \( L^2 T^{-1} \) Since the dimensions of options A, B, and C are the same, while option D has a different dimension, the answer is: **Option D has a different dimension from the other three.**
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