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A man travels two-third part of his tota...

A man travels two-third part of his total distance with speed `v_(1)` and rest one-third part with speed `v_(2)`. Find out the average speed of the man?

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To find the average speed of a man who travels two-thirds of his total distance with speed \( v_1 \) and the remaining one-third with speed \( v_2 \), we can follow these steps: ### Step 1: Define the total distance Let the total distance be \( s \). ### Step 2: Calculate the distances for each segment - Distance covered at speed \( v_1 \): \[ d_1 = \frac{2}{3}s \] - Distance covered at speed \( v_2 \): \[ d_2 = \frac{1}{3}s \] ### Step 3: Calculate the time taken for each segment - Time taken to cover the first segment (\( t_1 \)): \[ t_1 = \frac{d_1}{v_1} = \frac{\frac{2}{3}s}{v_1} = \frac{2s}{3v_1} \] - Time taken to cover the second segment (\( t_2 \)): \[ t_2 = \frac{d_2}{v_2} = \frac{\frac{1}{3}s}{v_2} = \frac{s}{3v_2} \] ### Step 4: Calculate the total time taken The total time \( T \) is the sum of the two times: \[ T = t_1 + t_2 = \frac{2s}{3v_1} + \frac{s}{3v_2} \] ### Step 5: Simplify the total time expression To combine the fractions, we need a common denominator: \[ T = \frac{2s}{3v_1} + \frac{s}{3v_2} = \frac{2s v_2 + s v_1}{3v_1 v_2} = \frac{s(2v_2 + v_1)}{3v_1 v_2} \] ### Step 6: Calculate the average speed The average speed \( V_{avg} \) is defined as the total distance divided by the total time: \[ V_{avg} = \frac{\text{Total Distance}}{\text{Total Time}} = \frac{s}{T} \] Substituting the expression for \( T \): \[ V_{avg} = \frac{s}{\frac{s(2v_2 + v_1)}{3v_1 v_2}} = \frac{s \cdot 3v_1 v_2}{s(2v_2 + v_1)} \] Cancelling \( s \) from numerator and denominator: \[ V_{avg} = \frac{3v_1 v_2}{2v_2 + v_1} \] ### Final Answer Thus, the average speed of the man is: \[ V_{avg} = \frac{3v_1 v_2}{2v_2 + v_1} \]
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