Home
Class 12
PHYSICS
What is the maximum value of force, so t...

What is the maximum value of force, so that both the blocks will move together ?

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the maximum value of force \( F \) so that both blocks move together, we can follow these steps: ### Step 1: Identify the Given Values We have two blocks with the following properties: - Mass of block 1 (\( m_1 \)) = 2 kg - Mass of block 2 (\( m_2 \)) = 3 kg - Coefficient of friction for block 1 (\( \mu_1 \)) = 0.2 - Coefficient of friction for block 2 (\( \mu_2 \)) = 0.6 - Acceleration due to gravity (\( g \)) = 9.8 m/s² (assuming standard value) ### Step 2: Calculate the Maximum Static Friction Forces The maximum static friction force for each block can be calculated using the formula: \[ f_{\text{max}} = \mu \cdot m \cdot g \] For block 1: \[ f_{1} = \mu_1 \cdot m_1 \cdot g = 0.2 \cdot 2 \cdot 9.8 = 3.92 \, \text{N} \] For block 2: \[ f_{2} = \mu_2 \cdot m_2 \cdot g = 0.6 \cdot 3 \cdot 9.8 = 17.64 \, \text{N} \] ### Step 3: Set Up the Equations of Motion When both blocks are moving together, the force \( F \) must overcome the friction acting on both blocks. The total friction force opposing the motion is the sum of the friction forces acting on both blocks: \[ F_{\text{friction}} = f_{1} + f_{2} = 3.92 + 17.64 = 21.56 \, \text{N} \] ### Step 4: Apply Newton's Second Law For both blocks to move together, the applied force \( F \) must equal the total friction force: \[ F = f_{1} + f_{2} \] ### Step 5: Calculate the Maximum Force Thus, the maximum force \( F \) that can be applied so that both blocks move together is: \[ F = 21.56 \, \text{N} \] ### Conclusion The maximum value of force \( F \) so that both blocks will move together is approximately **21.56 N**. ---
Promotional Banner

Topper's Solved these Questions

  • RACE

    ALLEN|Exercise Basic Maths (WORK POWER & ENERGY)|34 Videos
  • RACE

    ALLEN|Exercise Basic Maths (CIRCULAR MOTION)|17 Videos
  • RACE

    ALLEN|Exercise Basic Maths (NEWTONS LAWS OF MOTION)|46 Videos
  • NEWTONS LAWS OF MOTION

    ALLEN|Exercise EXERCISE-III|28 Videos
  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise Example|1 Videos

Similar Questions

Explore conceptually related problems

Two block , with masses m_(1) and m_(2) are staked as shown in fig and placed on a frictionless horizontal surface . There is a friction between the two block .An external force of magnitude F is applied to the top block at an angle alpha below the horizontal . The coefficient of friction between m_(1) and m_(2) are mu_(s) b. If the two blocks move together, find their acceleration b . Calculate the maximum value of force so that blocks will move together

There are two block as shown in the figure of masses 1kg and 4kg . Friction coefficient between any two surfaces are 0.2 then find maximum value of horizontal force F so that both blocks moves together.

What is the minimum value of applied force F so that both the block lifts up. Consider string to be ideal. The mass of pulley P_(1) is 6 kg and pulley P_(2) is light.

What is the maximum value of the force F such that the block shown in the arrangement, does not move:

What is the maximum value of the force F such that the block shown in the arrangement, does not move?

What is the maximum value of the force F such that the block shown in the figure does not move?

In the sitution shown in figure there is no friction between 2 kg and ground. a. For what maximum value of force F can all three blocks move together? b. Find the value of force F at which sliding starts at other rough surfaces. c. Find acceleration of all blocks, nature and value of friction force for the following values of force F (i) 10N (ii) N and (iii) 25 N

The coefficient of static friction, mu_(s) between block A of mass 2 kg and the table as shown in the figure is 0.2. What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless. (g=10m//s^(2))

The coefficient of static friction, mu_(s) between block A mass 2kg and the table as shown in the figure, is 0.2. What would be the maximum mass value of block B, so that the two blocks do not move ? The string and the pulley are asseumed to be smooth and massless ( g=10m//s^(2) )

A block of mass 10 kg is kept on a rough inclined plane as shown in the figure. A force of 3 N is applied on the block. The coefficient of static friction between the plane and the block is 0.6 What should be the minimum value of force P, such that the block doesnot move downward? (take g=10ms^(-2) )