The height at which the acceleration due...

The height at which the acceleration due to gravity becomes `(g)/(9)` (where g = the accleeration due to gravity on the surface of the earth) in terms of R, the radius of the earth is

A

`(R)/(2)`

B

`sqrt(2)R`

C

2R

D

`(R)/(sqrt(2))`

Text Solution

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The correct Answer is:

C

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