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The excess pressure inside one soap bubb...

The excess pressure inside one soap bubble is three times that inside a second soap bubble, then the ratio of their surface area is:

A

`1 : 9`

B

`1 : 3`

C

`3 : 1`

D

`1 : 27`

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The correct Answer is:
To solve the problem, we need to understand the relationship between the excess pressure inside soap bubbles and their radii, and subsequently how this relates to their surface areas. ### Step-by-Step Solution: 1. **Understanding Excess Pressure in Soap Bubbles**: The excess pressure (ΔP) inside a soap bubble is given by the formula: \[ \Delta P = \frac{4T}{R} \] where \(T\) is the surface tension of the soap solution and \(R\) is the radius of the bubble. 2. **Setting Up the Relationship**: Let’s denote the excess pressure inside the first soap bubble as \(P_1\) and the second soap bubble as \(P_2\). According to the problem, we have: \[ P_1 = 3P_2 \] 3. **Expressing the Pressures in Terms of Radii**: Using the formula for excess pressure: \[ P_1 = \frac{4T}{R_1} \quad \text{and} \quad P_2 = \frac{4T}{R_2} \] Substituting these into the relationship gives: \[ \frac{4T}{R_1} = 3 \cdot \frac{4T}{R_2} \] 4. **Simplifying the Equation**: We can cancel \(4T\) from both sides (assuming \(T \neq 0\)): \[ \frac{1}{R_1} = \frac{3}{R_2} \] Rearranging this gives: \[ R_2 = 3R_1 \] 5. **Finding the Ratio of Surface Areas**: The surface area \(S\) of a soap bubble is given by: \[ S = 4\pi R^2 \] Therefore, the surface areas of the two bubbles can be expressed as: \[ S_1 = 4\pi R_1^2 \quad \text{and} \quad S_2 = 4\pi R_2^2 \] The ratio of their surface areas is: \[ \frac{S_1}{S_2} = \frac{4\pi R_1^2}{4\pi R_2^2} = \frac{R_1^2}{R_2^2} \] 6. **Substituting the Radius Relationship**: Since we found \(R_2 = 3R_1\), we can substitute this into the ratio: \[ \frac{S_1}{S_2} = \frac{R_1^2}{(3R_1)^2} = \frac{R_1^2}{9R_1^2} = \frac{1}{9} \] 7. **Final Ratio of Surface Areas**: Thus, the ratio of the surface areas of the two soap bubbles is: \[ \frac{S_1}{S_2} = \frac{1}{9} \] ### Conclusion: The ratio of the surface areas of the two soap bubbles is \(1:9\).
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