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A wave is given by the equation y = 1...

A wave is given by the equation
` y = 10 sin 2 pi (100 t - 0.02 x) + 10 sin 2 pi (100 t + 0.02 x)`
Find the loop length , frequency , velocity and maximum amplitude of the stationary wave produced.

A

20 units and 30 units

B

20 units and 25 units

C

30 units and 20 units

D

25 units and 20 units

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The correct Answer is:
To solve the problem, we need to analyze the given wave equation and extract the required parameters: loop length, frequency, velocity, and maximum amplitude of the stationary wave produced. ### Step-by-Step Solution: 1. **Identify the Wave Equation**: The given wave equation is: \[ y = 10 \sin(2\pi(100t - 0.02x)) + 10 \sin(2\pi(100t + 0.02x)) \] This represents two traveling waves moving in opposite directions. 2. **Determine the Frequency**: The angular frequency \(\omega\) is given by the term \(2\pi \times 100\). We can relate angular frequency to frequency \(f\) using the formula: \[ \omega = 2\pi f \] Thus, we can find \(f\): \[ f = 100 \text{ Hz} \] 3. **Calculate the Wavenumber \(k\)**: The wavenumber \(k\) can be determined from the term \(0.02x\): \[ k = 2\pi \times 0.02 = 0.04\pi \text{ rad/m} \] 4. **Find the Wavelength \(\lambda\)**: The relationship between wavenumber and wavelength is given by: \[ k = \frac{2\pi}{\lambda} \] Rearranging gives: \[ \lambda = \frac{2\pi}{k} = \frac{2\pi}{0.04\pi} = 50 \text{ m} \] 5. **Determine the Velocity \(v\)**: The wave velocity \(v\) can be calculated using the formula: \[ v = f \lambda \] Substituting the values: \[ v = 100 \times 50 = 5000 \text{ m/s} \] 6. **Calculate the Maximum Amplitude**: The maximum amplitude of the stationary wave is given by the superposition of the two waves. Since both waves have an amplitude of 10, the maximum amplitude \(A_{max}\) is: \[ A_{max} = 2 \times 10 = 20 \text{ units} \] 7. **Determine the Loop Length**: The loop length is half the wavelength: \[ \text{Loop Length} = \frac{\lambda}{2} = \frac{50}{2} = 25 \text{ m} \] ### Summary of Results: - **Loop Length**: 25 m - **Frequency**: 100 Hz - **Velocity**: 5000 m/s - **Maximum Amplitude**: 20 units
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