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Number of Acyclic bromoalkene from the m...

Number of Acyclic bromoalkene from the molecular formula `C_4H_7Br` (Structural only)

A

A. 6

B

B. 8

C

C. 7

D

D. 9

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To determine the number of acyclic bromoalkenes from the molecular formula \( C_4H_7Br \), we will follow these steps: ### Step 1: Calculate the Degree of Unsaturation (DU) The degree of unsaturation helps us understand how many rings or double bonds are present in the molecule. The formula for calculating DU is: \[ \text{DU} = \frac{(2C + 2 + N - H - X)}{2} \] Where: - \( C \) = number of carbon atoms - \( N \) = number of nitrogen atoms - \( H \) = number of hydrogen atoms - \( X \) = number of halogens (in this case, bromine) For \( C_4H_7Br \): - \( C = 4 \) - \( H = 7 \) - \( Br = 1 \) - \( N = 0 \) Substituting the values into the formula: \[ \text{DU} = \frac{(2 \times 4 + 2 + 0 - 7 - 1)}{2} = \frac{(8 + 2 - 7 - 1)}{2} = \frac{2}{2} = 1 \] ### Step 2: Understand the Implication of DU A DU of 1 indicates that there is either one double bond or one ring in the structure. Since we are looking for acyclic compounds, we will only consider the double bond. ### Step 3: Identify Possible Structures We will now draw the possible acyclic bromoalkenes with the formula \( C_4H_7Br \). The general structure will include a double bond and a bromine atom. 1. **1-Bromobut-1-ene**: \( CH_2=CH-CH_2-CH_2Br \) 2. **2-Bromobut-1-ene**: \( CH_2=CH-CH(Br)-CH_3 \) 3. **1-Bromobut-2-ene**: \( CH_3-CH=CH-CH_2Br \) 4. **3-Bromobut-1-ene**: \( CH_2=CH-CH_2-CH(Br)-CH_3 \) 5. **2-Bromobut-2-ene**: \( CH_3-C(Br)=CH-CH_3 \) 6. **1-Bromo-2-methylpropene**: \( CH_2=CH-CH(CH_3)-Br \) 7. **2-Bromo-2-methylpropene**: \( C(Br)=C(CH_3)-CH_3 \) ### Step 4: Count the Isomers After identifying the structures, we can count them: 1. 1-Bromobut-1-ene 2. 2-Bromobut-1-ene 3. 1-Bromobut-2-ene 4. 3-Bromobut-1-ene 5. 2-Bromobut-2-ene 6. 1-Bromo-2-methylpropene 7. 2-Bromo-2-methylpropene Thus, the total number of acyclic bromoalkenes is **7**. ### Final Answer The number of acyclic bromoalkenes from the molecular formula \( C_4H_7Br \) is **7**. ---
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