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An aeroplane flying 490 m above the grou...

An aeroplane flying 490 m above the ground level at 100 m/s, releases a block. How far on the ground will it strike-

A

`0.1 km`

B

`1 km`

C

`2 km `

D

none of the above

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The correct Answer is:
To solve the problem of how far on the ground the block will strike after being released from the aeroplane, we can break the solution down into several clear steps. ### Step 1: Identify the given values - Height (h) = 490 m - Speed of the airplane (v) = 100 m/s - Acceleration due to gravity (g) = 9.8 m/s² ### Step 2: Calculate the time taken for the block to fall The time (t) taken for the block to fall from the height can be calculated using the formula for free fall: \[ t = \sqrt{\frac{2h}{g}} \] Substituting the values: \[ t = \sqrt{\frac{2 \times 490}{9.8}} = \sqrt{\frac{980}{9.8}} = \sqrt{100} = 10 \text{ seconds} \] ### Step 3: Calculate the horizontal distance traveled by the block The horizontal distance (d) traveled by the block while it falls can be calculated using the formula: \[ d = v \times t \] Substituting the values: \[ d = 100 \text{ m/s} \times 10 \text{ s} = 1000 \text{ m} \] ### Step 4: Conclusion The block will strike the ground at a distance of 1000 meters from the point directly below where it was released. ### Final Answer The block will strike the ground 1000 meters away from the point of release. ---
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