`CH_(3)-CH_(2)-overset(O)overset(||)C-CH_(2) -CHO,` IUPAC name of compound is :-

Options

A. 3-Oxo pentanal
B. 3-formyl pentanal
C. 1-Formyl butan-2-one
D. Pentane-1, 3-dial

Answer

To determine the IUPAC name of the compound \( CH_3-CH_2-C(=O)-CH_2-CHO \), we can follow these steps:

### Step 1: Identify the Longest Carbon Chain
The first step is to identify the longest continuous carbon chain in the compound.

- The structure can be represented as:
\[ CH_3-CH_2-C(=O)-CH_2-CHO \]
- Counting the carbon atoms, we find there are 5 carbon atoms in total.

### Step 2: Determine the Parent Alkane
Since there are 5 carbon atoms, the parent alkane is **pentane**.

### Step 3: Number the Carbon Atoms
Next, we need to number the carbon atoms in the chain. The numbering should be done in such a way that the functional groups receive the lowest possible numbers.

- Starting from the right (where the aldehyde group \( -CHO \) is located), we number the carbons:
- Carbon 1: \( CHO \) (aldehyde)
- Carbon 2: \( CH_2 \)
- Carbon 3: \( C(=O) \) (oxo group)
- Carbon 4: \( CH_2 \)
- Carbon 5: \( CH_3 \)

### Step 4: Identify Functional Groups
Now, we identify the functional groups present in the compound:
- At carbon 1, we have an aldehyde group (CHO).
- At carbon 3, we have a ketone group (C=O), which is referred to as an oxo group.

### Step 5: Combine Information to Form the IUPAC Name
The presence of the aldehyde group takes precedence in naming. The suffix for aldehydes is **-al**, and for ketones, we use the prefix **oxo**.

- The IUPAC name will be constructed as follows:
- The parent name is **pentane**.
- The oxo group is at carbon 3, so we write **3-oxo**.
- Since we have an aldehyde, we replace the ending **-e** of pentane with **-al**.

Thus, the final IUPAC name of the compound is **3-oxopentanal**.

### Final Answer:
The IUPAC name of the compound \( CH_3-CH_2-C(=O)-CH_2-CHO \) is **3-oxopentanal**.

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