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[" The number of ways in which we can choose a committee from "],[" four men and six women so that the committee includes at least "],[" two men and exactly twice as many women as men is "],[[" (A) "49," (B) "126," (C) "128," (D) "94]]

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To solve the problem of choosing a committee from four men and six women such that the committee includes at least two men and exactly twice as many women as men, we can break it down into cases: ### Step-by-Step Solution: 1. **Identify the cases based on the number of men:** - Since we need at least two men, we can have either: - Case 1: 2 men and 4 women - Case 2: 3 men and 6 women ...
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