Which is/are correct about electronegativity order of the following elements ?

Options

A. `P gt Si`
B. `C gt N`
C. `C gt Br`
D. `Sr gt Ca`

Answer

To determine the correct electronegativity order of the given elements, we will analyze each option based on the known trends in electronegativity.

### Step-by-Step Solution:

1. **Understanding Electronegativity**: Electronegativity is the tendency of an atom to attract electrons in a chemical bond. The most electronegative element is fluorine, followed by oxygen, nitrogen, and then carbon and silicon.

2. **Analyzing Each Option**:
- **Option 1: P > Si**:
- Phosphorus (P) belongs to the nitrogen group and is more electronegative than silicon (Si), which is in the carbon group.
- **Conclusion**: This statement is correct.

- **Option 2: C > N**:
- Carbon (C) is less electronegative than nitrogen (N). The electronegativity of nitrogen is higher than that of carbon.
- **Conclusion**: This statement is incorrect.

- **Option 3: C > Br**:
- Bromine (Br) is a halogen and is more electronegative than carbon (C).
- **Conclusion**: This statement is incorrect.

- **Option 4: Sr > Ca**:
- Strontium (Sr) and Calcium (Ca) are both in Group 2 of the periodic table. They have similar electronegativities, but they are not greater than one another.
- **Conclusion**: This statement is incorrect.

3. **Final Conclusion**: Based on the analysis, the only correct statement regarding electronegativity is **Option 1: P > Si**.

### Summary of Correct Options:
- Correct: Option 1 (P > Si)
- Incorrect: Options 2 (C > N), 3 (C > Br), and 4 (Sr > Ca)