Identify the correct option

Options

A. `NO_(3)^(-) gt NH_(3) gt NH_(2)^(-)` (order of bond angle)
B. `(CH_(3))_(3)` B is a planar molecule
C. In `NH_(4)Cl`, .N. atom is in `sp^(3)d` Hybridisation
D. `BF_(3) lt BCl_(3) lt B Br_(3) lt BI_(2)` (Order of bond angle)

Answer

A

Explanation

(i) `underset(sp^(2))(NO_(3)^(-)) gt underset("1 lp")underset(sp^(3))(NH_(3)) gt underset("2 lp")underset(sp^(3))(NH_(2)^(-))` (B.A. order)
(ii) In `(CH_(3))_(3)` B hyb. of carbon is `sp^(3)` (non planar)
(iii) `NH_(4)Cl to NH_(4)^(+)Cl^(-)` in `NH_(4)^(+)` hyb. of N is `sp^(3)`
(iv) In `s_(8)` molecule total 16 lp or 32 non bonded `e^(-)`