Number of carbon atom present linearly in `C_(3)O_(2)` :-

Options

A. 2
B. 3
C. 6
D. 1

Explanation

To determine the number of carbon atoms present linearly in the compound \( C_3O_2 \) (carbon suboxide), we can follow these steps:

### Step 1: Understand the Structure of Carbon Suboxide
Carbon suboxide has the molecular formula \( C_3O_2 \). It consists of three carbon atoms and two oxygen atoms. The structure of carbon suboxide can be represented as \( O=C=C=C=O \).

### Step 2: Analyze the Bonding
In the structure \( O=C=C=C=O \):
- The first carbon is double bonded to the first oxygen and double bonded to the second carbon.
- The second carbon is double bonded to the first carbon and double bonded to the third carbon.
- The third carbon is double bonded to the second carbon and double bonded to the second oxygen.

### Step 3: Identify Linear Arrangement
The arrangement of the atoms shows that all three carbon atoms are in a straight line. The linear structure is due to the double bonds between the carbon atoms, which do not allow for any bending or angles that would disrupt linearity.

### Step 4: Count the Linear Carbon Atoms
Since all three carbon atoms are arranged in a straight line, we can conclude that there are three linear carbon atoms in carbon suboxide.

### Conclusion
The number of carbon atoms present linearly in \( C_3O_2 \) is **3**.

### Final Answer
The answer is **3**.

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