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Which of the following compounds give pa...

Which of the following compounds give paramagnetic gas on decomposition
(i) `Pb(NO_(3))_(2)`
(ii) `LiNO_(3)`
(iii) `NaNO_(3)`
(iv) `NH_(4)NO_(2)`

A

I, II, III

B

II, III

C

I, II

D

III, IV

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The correct Answer is:
To determine which of the given compounds produce paramagnetic gases upon decomposition, we will analyze each compound and its decomposition products. ### Step-by-Step Solution: 1. **Identify the Compounds**: The compounds given are: - (i) Pb(NO₃)₂ (Lead(II) nitrate) - (ii) LiNO₃ (Lithium nitrate) - (iii) NaNO₃ (Sodium nitrate) - (iv) NH₄NO₂ (Ammonium nitrite) 2. **Decomposition Reactions**: - **(i) Pb(NO₃)₂**: Upon heating, lead(II) nitrate decomposes to produce nitrogen dioxide (NO₂) and oxygen (O₂): \[ 2 \text{Pb(NO}_3\text{)}_2 \rightarrow 2 \text{PbO} + 4 \text{NO}_2 + \text{O}_2 \] Both NO₂ and O₂ are paramagnetic gases because they have unpaired electrons. - **(ii) LiNO₃**: Lithium nitrate decomposes to produce lithium oxide, nitrogen dioxide, and oxygen: \[ 2 \text{LiNO}_3 \rightarrow \text{Li}_2\text{O} + 2 \text{NO}_2 + \text{O}_2 \] Again, both NO₂ and O₂ are paramagnetic. - **(iii) NaNO₃**: Sodium nitrate also decomposes similarly: \[ 2 \text{NaNO}_3 \rightarrow 2 \text{Na}_2\text{O} + 2 \text{NO}_2 + \text{O}_2 \] Here too, NO₂ and O₂ are paramagnetic. - **(iv) NH₄NO₂**: Ammonium nitrite decomposes to produce nitrogen gas (N₂) and water: \[ \text{NH}_4\text{NO}_2 \rightarrow \text{N}_2 + 2 \text{H}_2\text{O} \] Nitrogen gas (N₂) is diamagnetic because it has no unpaired electrons. 3. **Conclusion**: The compounds that produce paramagnetic gases upon decomposition are: - Pb(NO₃)₂ - LiNO₃ - NaNO₃ Thus, the answer is (i), (ii), and (iii). ### Final Answer: The compounds that give paramagnetic gas on decomposition are (i) Pb(NO₃)₂, (ii) LiNO₃, and (iii) NaNO₃.
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Arrange the following compounds in order of increasing molar conductivity . (i) K[Co(NH_(3))_(2)(NO_(2))_(4)]" " (ii) [Cr(NH_(3))_(3)(NO_(2))_(3)] (iii) [Cr(NH_(3))_(5)(NO_(2))]_(3)[Co(NO_(2))_(6)]_(2)" " (iv) [Cr(NH_(3))_(6)]Cl_(3)

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